SQL基础：RANK 排名 SQLServer RANK() 排名函数的使用

— 例子表数据
SELECT * FROM test;
— 统计分数
SELECT name,SUM(achievement) achievement FROM test GROUP BY name;
— 按统计分数做排行
SELECT RANK() OVER( ORDER BY SUM(achievement) desc) 排行,name,SUM(achievement) achievement FROM test GROUP BY name;

USE [DB]
GO

/****** Object: StoredProcedure [dbo].[sp_TodayJoinUser] Script Date: 2021/1/26 14:45:24 ******/
SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER ON
GO

— =============================================
— Author: _Hey_Jude
— Create date: 2021-01-26
— Description: 获取今日发表帮助/回复的新用户
— =============================================
CREATE PROCEDURE [dbo].[sp_TodayJoinUser]
@tableLevel int,
@date varchar(30)
AS
Declare @Sql nvarchar(max)
declare @minTabId int
declare @maxTabId int
declare @maxf_id int
declare @helpTableName nvarchar(max)
declare @tableCount int

BEGIN
–最小f_id所在表
set @minTabId=0
set @tableCount=@minTabId
–最大f_id所在表
set @maxf_id=(select MAX(F_ID) from [Table] where F_IsDelete=0)
set @maxTabId=@maxf_id/@tablelevel

set @helpTableName=’SELECT UserID, Max([F_DateTime]) AS dt FROM [Table] GROUP BY UserID’

while @tableCount<=@maxTabId
begin
print @tableCount
set @helpTableName += ‘ UNION SELECT UserID, Max([DateTime]) as dt FROM SubTable’+cast(@tableCount as nvarchar(10))+’ GROUP BY UserID ‘
set @tableCount=@tableCount+1
end

set @Sql=’SELECT [nikename] FROM (
SELECT UserID, RANK() OVER(PARTITION BY UserID ORDER BY dt) AS Num,dt FROM ( ‘+@helpTableName+’ ) AS T ) AS NewT
LEFT JOIN [UserTable] A WITH(NOLOCK) ON NewT.UserID = A.UserId WHERE Num = 1 AND dt > ”’+@date+””

Exec sp_executesql @Sql
END

GO

SELECT* FROM (
SELECT
ROW_NUMBER() over(partition by [姓名] order by [打卡时间] desc) as rowNum,
[姓名],
[打卡时间]
FROM [dbo].[打卡记录表]
) temp
WHERE temp.rowNum = 1